Question

In the figure AB parallel to CD. If angle ABR = 45 degree and angle ROD = 105 degree then find angle ODC

Answer 1

Let us construct the lines OQand RP.∠ABO= ∠BPD = 45°In △OPD, ∠OPD +∠POD+∠ODP= 180°or, 45° +105° +∠ODP = 180°or, ∠ODP= 180° − 45° − 105° = 30°Thus, ∠ODC= 30°

Answer 2

Here is your answer.....