In the figure AB parallel to CE. If area of triangle ADB is 100sq cm find the area of triangle AEB and triangle ACB
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ΔAEB = 100 sq. cm
ΔACB = 100 sq. cm
Step-by-step explanation:
Given that,
In the ║gm ABCE, AB is ║ to CE
In ΔADB and ΔAEB
AB = AB (common base)
Both Δs are drawn between the same parallel lines
As per Theorem 1, two Δs with the same base and in between same ║ lines are equal in area
∵ ΔADB = ΔAEB = 100 sq. cm
Using the same theorem,
In ΔACB,
AB is the same base again and it is also drawn between the same ║ lines.
∵ ΔADB = ΔAEB = ΔACB = 100 sq. cm
Learn more: theorem
brainly.in/question/15838107
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