Question

In the figure AB ǁ PQ AND ABM = 125⁰and MPQ = 110⁰, Find BMP​

Answer 1

Correct option is

C

55∘

Given, ∠AOB=110∘

In △AOB

OA=OB (Radius of the circle)

Thus, ∠OAB=∠OBA (Isosceles triangle property)

Sum of angles of the triangle = 180

∠AOB+∠OAB+∠OBA=180

110+2∠OBA=180

∠OBA=35∘

Since, PQ is a tangent touching the circle at B.

Thus, ∠OBQ=90∘

Now, ∠ABQ+∠OBA=90

∠ABQ+35=90

∠ABQ=55∘

Answer 2

Step-by-step explanation:

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