Question

In the figure AB, PQ are parallel the area of triangle ABP 100cm2 .Find the area of triangle ABQ​

Answer 1

Answer:

100 cm2

Step-by-step explanation:

since AB and PQ are parallel the area of both the triangle will be the same

Answer 2

Answer:

A parallelogram ABCD of area 100 unit². P is the midpoint of the side BC.

Join AC.

The diagonal AC divides the parallelogram ABCD into two triangles of equal area.

Area ∆ ABC = Area ∆ ACD = ½ Area of parallelogram ABCD = ½ × 100 unit²

Now ∆ ABP, and ∆ APC lie between the same two parallel sides AD and BC of the parallelogram ABCD and have their bases BP and PC are also equal being ½ of side BC.

Therefore,

Area of ∆ ABP = Area of ∆ APC (triangles lying between same two parallel lines and having equal bases)

Therefore

Area ∆ ABP = Area ∆ APC = ½ Area of ∆ ABC = 14 Area of parallelogram ABCD = 25 unit².