In the figure, AB=QR, AC=PQ, BC=PR. Also
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∴ The angles of ∆ ABC and ∆ PQR are equal.
∠A = ∠P, ∠B =∠Q, ∠C = ∠R
(a) AB||PQ,
∴ ∠B = ∠PMN (corresponding angle);
∴ ∠PMN = ∠Q
∴ MN||QR
∴ BC||QR
(b) BC||QR
∠R = ∠MNP = ∠C
∴ NP||AC, PR||AC
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