Question

In the figure ABC and CDE are right angle triangle in which angle abc is equal to 90 degree angle CDE is equal to 90 degree angle ACB is equal to theta angle is ECD is equal to phi AB is equal to 4 m and ED is equal to 3m if sin theta is equal to 5 by 13 and Cos phi is equal to 3 by 5 find the length of BD​

Answer 1

Step-by-step explanation:

since in triangle ABC

sine theta =5/13=perpendicular/hypotnious

i,e AB/Ac=5/13

4/AC= 5/13

AC=10.4

Now in triangle EDC

COS phi= Base/hypotnious

CD/CE = 3/5

CD=(3/5)CE

By Pythagoras theorem

CE=

$\sqrt{22.5}$

there fore CD = (3/5)√22.5= 2.84

therefore BD= BC+CD

BD=10.4+2.84

BD= 13.25

Answer 2

Answer:

Step-by-step explanation:

Answers

Aabidrashid

AabidrashidHelping Hand

Step-by-step explanation:

since in triangle ABC

sine theta =5/13=perpendicular/hypotnious

i,e AB/Ac=5/13

4/AC= 5/13

AC=10.4

Now in triangle EDC

COS phi= Base/hypotnious

CD/CE = 3/5

CD=(3/5)CE

By Pythagoras theorem

CE=

\sqrt{22.5}

there fore CD = (3/5)√22.5= 2.84

therefore BD= BC+CD

BD=10.4+2.84

BD= 13.25