In the figure, ABC is a right-angled triangle, ZB= 90°, AB = 28cm and BC = 21cm. With AC as diameter, a semicircle is drawn and with BC as radius a quarter circle is drawn.
Find the area of the shaded region.
Answers
Answer:
and
Step-by-step explanation:
Draw orbital diagrams for the formation of the following compounds.
(1) Sodium chloride
(ii) Water
Answer:
Area of the shaded region = 444.5cm²
Step-by-step explanation:
Given :
A triangle with (height)h = 28 cm
(base)b = 21cm
semi circle with diameter as AC
quadrant circle wit BC as radius
solution :
AC = √BC² + AC² (Pythagoras theorem)
AC = √441 + 784
AC = √1225
AC = 35cm
Area of the triangle = 1/2(b)(h)
= 1/2(21)(28)
= 21 x 14
= 294 cm²
Area of a Quadrant = πr²/4
= π(21)(21)/4
= 22/7(21)(21)/4
= (22 x 3 x 21)/4
= (1323/4)
= 330.75 cm²
Area of semicircle = πr²/2
= 22/7 (35/2)(35/2)/2
= 22 x 5/2 x 35/2 / 2
= 481.25 cm²
Area of shaded part = (area of triangle+area of semicircle)-area quadrant
= (294 + 481.25) - 330.75
= (775.25) - 330.75
= 444.5 cm²
Area of the shaded region = 444.5cm²
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