Question

In the figure ABC is a right triangle and right angled at
B such that angleBCA=2BAC.
Show that hypotenuse AC=2BC.
(Hint: Produce CB to a point D that BC = BD )​
please answer me fast

Answer 1

Answer:

Step-by-step explanation:

∠BAC= x then ∠BCA = 2x

x + 2x = 90° , 3x = 90° ==> x = 30°

Property of right Δ : leg opposite to 30° = $\frac{1}{2}$ of hypotinuse

==> AC = 2BC