In the figure ABC is a right triangle right angled at b. Ad and CE are two medians drawn from A And c respectively . If Ac =5 and AD =3root5/2 find the length of ce
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by Pythagoras
in triangle ABD
AB²+1/4BC²=AD² it is equation 1
in triangle BCE
BC²+1/4AB²=CE² it is equation 2
add equation 1 & 2
AB²+BC²+1/4BC²+1/4AB²=AD²+
in triangle ABD
AB²+1/4BC²=AD² it is equation 1
in triangle BCE
BC²+1/4AB²=CE² it is equation 2
add equation 1 & 2
AB²+BC²+1/4BC²+1/4AB²=AD²+
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