Question

In the figure, ABC is a triangle and a line XY is parallel to the line BC. If XY cuts AB at X and AC at Y, BY bisects angle XYC, prove that angle CBY=angle CYB. [ Hint:since XY||BC, so angle XYB=angle CBY. Also,angle XYB= angle CYB. : Angle CBY= Angle CYB]
​

Answer 1

Answer:

the answer to your question hope it helps