Question

in the figure ABC is a triangle BD perpendicular AC prove that a b square + C D square equal to 80 square + BC square​

Answer 1

Step-by-step explanation:

ABD is a right angled traingle

and AB is the hypotaneous

(AB)^2 = (AD)^2 + (BD)^2

(AB)^2 - (BD)^2 = (AD)^2 ---------(i)

now,

ACD is also a right angled traingle

(AC)^2 = (AD)^2 + (DC)^2

(AC)^2 - (DC)^2 = (AD)^2 ----------(ii)

(i) = (ii)

(AB)^2 - (BD)^2 =(AC)^2 - (DC)^2

(AB)^2 +(DC)^2 = (AC)^2 + (BD)^2