Question

in the figure ABC is a triangle in which angle is the midpoint of a b and n is a point on BC such that a n is equal to 2 C and a line through hell parallel to BC and meets AC at M2 that I am is equal to cm

Answer 1

Answer:

Step-by-step explanation:

In ∆ABC, we have

M is the midpoint of AB and MD||BC

D is the midpoint of AC {by converse of midpoint theorem}

Now

MP||BC

<MDC+<BCD=180°

<MDC+90°=180°

<MDC=90°

Thus;MD perpendicular AC

Join MC

In ∆MDA and ∆MDC we have

DA=DC

<MDA=<CDM

MD=MD

∆MDA~∆MDC {S.A.S}

And so MA=MC

Now M is the midpoint of AB

MA=MC=1/2AB