In the figure,ABC is a triangle in which L is the mid-point of AB and N is a pint on AC such that AN=2CN.A line through L,parallel to BN meets AC at M.Prove that AM=CN
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given that ,
L is the midpoint of side AB of ΔABC and N is the point on AC i.e. AN = 2CN .
We have to prove - AM = CN
Proof ,
in Δ ANB .
By using convs. of midpoint theoram .
M is also a midpoint of AN
⇒ AM = MN
now ,
AN = 2CN
also , AM + MN = 2CN
AM + AM ( because AM = MN ) = 2 CN
2AM = 2 CN
.'. AM = CN ( Proved ).................
L is the midpoint of side AB of ΔABC and N is the point on AC i.e. AN = 2CN .
We have to prove - AM = CN
Proof ,
in Δ ANB .
By using convs. of midpoint theoram .
M is also a midpoint of AN
⇒ AM = MN
now ,
AN = 2CN
also , AM + MN = 2CN
AM + AM ( because AM = MN ) = 2 CN
2AM = 2 CN
.'. AM = CN ( Proved ).................
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