in the figure abc is an equilateral triangle and pqrs is a square of side 6cm find how much are of triangle is greater than the area of square
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Triangle ABC is similar toABC
AP/AB=PQ/BC=6/BC
PQ=6
Height of APQ=3(root3)
Height of ABC =6+3(root3)
Side of ABC=6+4(root3)
Area of ABC =36+21(root 3)
Area of square is=36
Area of triangle more than a square is 21(root)
AP/AB=PQ/BC=6/BC
PQ=6
Height of APQ=3(root3)
Height of ABC =6+3(root3)
Side of ABC=6+4(root3)
Area of ABC =36+21(root 3)
Area of square is=36
Area of triangle more than a square is 21(root)
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