in the figure ABC is an equilateral triangle of side 14 cm and BC is a diameter of semi circle find the area and perimeter of the figure take 5 22 upon 7 root 3 1.732
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Area of shaded part = Area of equilateral △ABC + Area of semi circle
= √3/4 a2 + 1/2 πr2
Given a = 14 cm and r = 14/2 = 7 cm
∴ Area of shaded part = √3/4 × 142 + ½ × 22/7 × 7 × 7
= (1.732 × 14 × 14)/4 + 11 × 7
= 1.732 × 7 × 7 + 77 = 84.868 + 77
= 161.868 sq. cm.
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