Question

in the figure ABC is right angle triangle in which angle B=90degree BC=6cm and Angle C=60 degree then the length of AC is​

Answer 1

Answer:

length of ac is ab minus ac

Answer 2

Answer:

Draw a right angled △ABC using given instructions:

Draw a right angled △ABC using given instructions:Here sin30=

Draw a right angled △ABC using given instructions:Here sin30= AC

Draw a right angled △ABC using given instructions:Here sin30= ACBC

Draw a right angled △ABC using given instructions:Here sin30= ACBC

Draw a right angled △ABC using given instructions:Here sin30= ACBC

Draw a right angled △ABC using given instructions:Here sin30= ACBC 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 =

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cm

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB)

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB)

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC)

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20)

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10)

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10) 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10) 2

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10) 2 =300

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10) 2 =300AB=10

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10) 2 =300AB=10 3

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10) 2 =300AB=10 3

Draw a right angled △ABC using given instructions:Here sin30= ACBC 21 = 20BC Or BC=10 cmBy Pythagoras theorem:(AB) 2 =(AB) 2 −(BC) 2 =(20) 2 −(10) 2 =300AB=10 3 cm.