In the figure, ABC is right-angled at B and BRS is right-angled
at R. If AB = 18 cm, BC = 7.5 cm, RS = 5 cm, BSR = x° SAB = yº, then
find :
(i) tan xº
(ii) sin yº
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- given SR= equal to 5 centimetre
CD = 7.5 CM ,
- AB equals to 18 centimetres
- so let us consider
AR +RB=AB
- let ,RB=X and AR =18-X
by similar triangles
remaining will be in the photo .
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