Question

in the figure ∆abc is similar to ∆xyz and ad and xe are angle bisectors of angle a and angle X respectively. find the ratio of areas of ∆abd and area of ∆xye​

Answer 1

Step-by-step explanation:

By Theorem- the ratio of area of two similar triangles is equal to the ratio of the squares of their corresponding internal angle bisector sengments.

Area of abc/area of xyz = ad^2÷xe^2