Question

In the figure ABCD and BEFG are two squares with side lengths 4 cm and 10 cm
respectively. The area of the shaded region (in cm) is.
4
6
40/7
10/7

Answer 1

Answer:

Given: AB=4cm

BE=10cm

F(14,10)

A(0,0)

Let A be the origin then equation of line AF

y=mxm=

x

2

−x

1

y

2

−y

1

=

10−0

14−0

y=

5

7

x

for x=4 cmy=

5

28

cm which are co-ordinates of P.

P(4,

5

28

)

Area of △APB

⇒

2

1

×base×height=

2

1

×AB×BP

=

2

1

×A×

5

28

=11.2 cm

2

.