In the figure ABCD, BD = BC=AD and
angle ACD =37. Find angle ADB.
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Step-by-step explanation:
L BCD = L CDB = 37° [ angles opposite to equal sides]
By angle sum property in triangle BDC
L CBD = 180- 2×37 = 180 - 74 = 106°
L DBC + L DBA = 180 ( angles on line)
L DBA = 180 - 106 = 74°
similarly in triangle ABD
L DBA + L DAB + y = 180
L DBA = L DAB =74
y = 180-2×74 = 180 - 148 = 32°
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