In the figure,abcd is a cyclic quadrilateral in which ac and bd are diagonal.if
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what we hv to find
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Find angle BDA
Bro in which figure at the top or at the bottom
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i got the answer pls dontsend
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Answer: 50°
Step-by-step explanation:
angle ACB = angle BDA (alt. segment)
so, angle BDA = 70°
in triangle ABD, angle A+ angle ABD + angle ADB = 180° (ASP)
= 60 + 70 + angle BDA = 180°
= BDA = 180 - 130 = 50°
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