in the figure ABCD is a cyclic quadrilateral side DC of the quadrilateral is produced to point p if angle BCP - 110 find angle BAD
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Given, ABCD is a cyclic quadrilateral
and ∠BAD=120
o
.
Since, ABCD is a cyclic quadrilateral,
∴∠BCD+∠BAD=180
o
...[Opposite angles of cyclic quadrilateral are supplementary].
⟹∠BCD=180
o
−∠BAD
=180
o
−120
o
=60
o
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