Question

In the figure ABCD is a parallelogram (ade= 50) and( ace= ( bed =90) the
value of the( EAC= (ABC - 2( DAC is

Answer 1

Answers the question pls soon

Answer 2

I think the question is to find

  ∠EAC+∠ABC-2.∠DAC

Here,

∠ACE = 90,∠ ADE = 50, ∴∠DAC = 40

∠ACE = 90, ∠BED=90, Then ∠AEC =45 and ∠EAC=45

∠ABC = 45  [∵180-(90+45)]

∠EAC+∠ABC-2.∠DAC = 45+45-2×40 = 90 - 80 = 10