Question

in the figure ABCD is a parallelogram. Also seg AM perpendicular seg BC
and seg CN Perpendicular seg AD.
Then prove that the A(∆AMB) = A(∆CND)​

Answer 1

In △ AMB and △CND

∠ABM = ∠CDN ....{OPPOSITE ANGLE OF ||gran}

∠AMD = ∠CND .....90°

side DC = Side AB .....opposite sides are congruent.

•°•△ AMB = △CND ..... ASA test of congruence

•°• A(△ AMB) = A(△CND)

Hence it is proved that A(△ AMB) = A(△CND)