Question

In the figure, ABCD is a parallelogram and CDEF is a trapezium. DE || CF,
ZBEF = 128° and _EFC = 48º. Find angle EDA​

Answer 1

Answer:

< BEF + < FEC = 180 (linear equation)

= 128 + < FEC = 180

= < FEC = 180 - 128

= < FEC = 52

and < FEC + < CED = < FED (1)

now, < FED + < EFC = 180 co-interior angle

= < FEC + < CED + < EFC = 180 from (1)

= < CED + 52 +48 = 180

= < CED = 180 - 100

= < CED = 80°

now, < CED = < EDA = 80°

( alternate interior angles)

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