In the figure ABCD is a parallelogram and DAB = 60°. The bisectors AP and BP of angles A and
B respectively meet at P on CD. If
CD
=K, then K
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If the bisector of angles A and B meet at M on CD, prove that M is the ... 1.5k views ... 8.36, P is the mid-point of side BC of parallelogram ABCD, such that ∠1 = ∠2.
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