Question

In the figure, ABCD is a parallelogram
in which DAP = 20°, BAP = 40° and
ABP = 80°. Find APD and BPC.​

Answer 1

Answer:

APD = 40°

BPC = 80°

Step-by-step explanation:

APD =40° ( By alternative interior angle )

BPC =80° (by alternative interior angle)

Answer 2

Answer:

APD=40°

BPC=80°

Step-by-step explanation:

W.K.T,

DA║AB, PA acts as a transversal

∴APD=PAB=40°(alternate interior angles)

PAB+PBA+APB=180°(angle sum)

40°+80°+ABP=180°

ABP=180°-120°=60°

W.K.T,

APD+APB+BPC=180°

∴40°+60°+BPC=180°

BPC=180°-100°=80°

∴APD=40°

∴BPC=80°