Question

in the figure ABCD is a parallelogram. M is a point on side AB, If ar triangle (DMC)=40 cm²
(1) Find ar (ABCD)
2)Write the relation between ar (ABCD) and ar (∆DMC)​

Answer 1

Answer:

(i) 80cm² (ii) ar(DMC)=½ar(ABCD)

Step-by-step explanation:

(i)Given:- In parallelogram ABCD ar(DMC)=40cm²

To find:- ar(ABCD)

Solution:- In parallelogram ABCD

ar(DMC)=½ar(ABCD). [If a triangle and a parallelogram

are on the same base then the

area of the triangle is half of the

area of parallelogram]....(i)

So,

40=½ar(ABCD)

ar(ABCD)=40×2

ar(ABCD)=80cm²Ans.

(ii)In parallelogram ABCD

ar(DMC)=½ar(ABCD). [From equation (i)]

Hence the relation between ar(DMC)and ar(ABCD) is that ar(DMC)=½ar(ABCD).