Question

In the figure ABCD is a parallelogram. The

diagonals AC and BD intersect at O; and ∠DAC = 40°, ∠CAB = 35°;

and ∠DOC = 110°. Calculate the ∠ABO, ∠ADC, ∠ACB, and ∠CBD.​

Answer 1

Answer:

chkg you have a ands ans asns

Answer 2

Answer:

ABCD is a parallelogram, Diagonals AC and BD at O

Explanation:

Given: DAC = 40°, CAB = 35° , DOC = 110°

angle ABO = 35° [ angle sum property i.e., OAB+AOB+ABO=180]

angle ADC =70°

angle ACB = 55°

angle CBD 55°