in the figure, ABCD is a quadrilateral
AC is the diagonal and EllAC and
also De meets Be Produced at E.
Show that are [ABCD] =ar[LABE]
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Given: ABCD is a quadrilateral, AC is diogonal And DE ∣∣ AC and also DE meats BC produced at E.
ΔDAC and ΔEAC lie on same base and between the parallel line DE and AC
Step-by-step explanation:
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