In the figure, ABCD is a quadrilateral in which AB=AD and BC=DC. Prove that 1:AC bisects each of the angles A and C
2: BE=BD
3: angle ABC = angle ADC
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Hope this helps you
And I think that their is some error in part 2 of this question it's BE=BD
But then where is point E
And I think that their is some error in part 2 of this question it's BE=BD
But then where is point E
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Answered by
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Answer:
in triangle ADC and triangle Abc
AD=AB [Given]
BC=DC
AC=AC (COMMON)
Triangle ADC ≈ triagle ABC
∠BAC=∠DAC
∠BCA=∠ACD
AC BESICTS ∠A and ∠C
\also ∠abc=∠abd
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