In the figure ABCD is a rectangle. AB = 10cm, BC = 8cm. P is a point on the line CD. M is the midpoint of PB.
a) What is the area of rectangle ABCD?
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Answer:
the area of rectangle is 80 cm
Step-by-step explanation:
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Solution :-
given that,
→ AB = Let length of rectangle = 10 cm
→ BC = Let breadth of rectangle = 8 cm .
So,
→ Area of rectangle ABCD = Length * Breadth
→ Area of rectangle ABCD = 10 * 8
→ Area of rectangle ABCD = 80 cm² (Ans.)
Hence, the area of rectangle ABCD is equal to 80 cm² .
Learn more :-
Diagonals AC and BD of quadrilateral ABCD meet at E. IF AE = 2 cm, BE = 5 cm, CE = 10 cm, 8 सेमी.
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Let abcd be a rectangle. the perpendicular bisector of line segment bd intersect ab and bc in point e and f respectively...
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