Question

in the figure ABCD is a rectangle and pqrs is a square find the area of shaded regions.​

Answer 1

Area of shaded region in rectangle ABCD is 85 cm².

Area of shaded region in square PQRS is 490 cm².

To find : Area of shaded region.

Given :

From the two figure,

Note : Figure has been attached below.

ABCD is a rectangle.

PQRS is a square.

Formula :    

Area of rectangle = $length \times width$

Area of square = $side \times side$

Area of triangle =  $\frac{1}{2}\times\{base\}\times\{height\}$    

In rectangle ABCD,

Area of shaded region = Area of rectangle - Area of unshaded region.

Area of unshaded region = Area of triangle ( I + II + III )

Area of triangles :          

Area of triangle ( I ) = $\frac{1}{2}\times6\times8 = 24$

Area of triangle ( II ) = $\frac{1}{2} \times4\times8=16$

Area of triangle ( III ) = $\frac{1}{2} \times 6\times (10- 5) = \frac{1}{2}\times6 \times5 = 15$

Area of unshaded region = 24 + 16 + 15 = 55

Area of rectangle ABCD = 10 × 14 = 140.

In rectangle ABCD, area of shaded region = 140 - 55 = 85 cm².

In square PQRS,

Area of shaded region = Area of square - Area of unshaded region.

Area of unshaded region

Area of triangles :          

Area of triangle ( I ) = $\frac{1}{2} \times14\times28=196$

Area of triangle ( II ) =$\frac{1}{2} \times14\times14 = 98$

Area of unshaded region = 196  + 98 = 294

Area of square PQRS = $28\times28$ $=784$

In square PQRS, area of shaded region = 784 - 294 = 490 cm².

To learn more...

1. In the given figure ABCD is a rectangle and pqrs is a square find the area of shaded regions.  Please tell me completely with steps.​                                                                      

brainly.in/question/15160024

2. In the given figure ABCD is a rectangle in which a b is equal to 40 cm and BC is equal to 25 CM if pqrs be the midpoint of Ab BC CD and da respectively find the area of the shaded region

brainly.in/question/2228902