Question

In the figure,ABCD is a rectangle, Finds the values of x and y (question from pair of linear equation in 2 variables)​

Answer 1

$\bf \underline{Given:- }$

$• \sf\: In \: the \: figure, \: ABCD \: is \: a \: rectangle.$

$• \sf \: Length, \: AB = 30 \: cm \: and \: CD = (x + y) \: cm$

$• \sf \: Breadth, \: AD = 14 \: cm \: and \: BC = (x-y) \: cm$

$\bf{ \underline{To \: Find :- }}$

$• \sf \: The \: Values \: of \: x \: and \: y$

$\huge\bf{ \underline{Solution :- }}$

$\sf{In \: the \: rectangle, \: AB = CD \: and \: AD= BC .}$

$\sf{According \: to \: the \: question, }$

$\sf{x + y = 30} \: \: \: (equation \: \: 1)$

$\sf{x-y=14} \: \: \: (equation \: \: 2 )$

$\sf{ \: equation \: (1) \: + \: equation \: (2), }$

$\sf x + y + x - y = 30 + 14$

$\rightarrow \sf 2x = 44$

$\rightarrow \sf x = 22$

$\sf{Putting\: the \: value \: of \: x \: into \: the \: equation \: (1), }$

$\sf22 + y = 30$

$\rightarrow \sf y = 30 - 22$

$\rightarrow \sf y = 8$

$\bf \red{Hence, \: the \: value \: of \: x \: is \: 22}$

$\bf \red{and \: the \: value \: of \: y \: is \: 8. }$