Math, asked by chandsalman860, 15 hours ago

in the figure ABCD is a rectangle. if the shaded area is 48 cm and Ab:BC=3:2 find the perimeter of rectangle.

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Answered by ethicalhacker7049
2

AREA OF SHADED AREA = AREA OF UNSHADED AREA = 48cm^2

LET THE RATIO BE 3x & 2x .

SO, AREA OF RECTANGLE = 2×48 = 96cm^2. [ BECAUSE ALL TRIANGLE IN A RECTANGLE HAVE EQUAL AREA ]

AGAIN, AREA OF RECTANGLE = (3x)×(2x) = 96cm^2 =] 6x^2 = 96

=]. x^2 = 96/6 = 16

=]. x = 4cm

SO, BREADTH AB = 3×4 = 12 cm

LENGTH BC = 2×4 = 8cm

SO, PERIMETER OF RECTANGLE = 2(l+b)

= 2(12+8) = 2×20 = 40cm

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