Question

In the figure ABCD is a rectangle.If the shaded area is 48cm and ab:bc=3:2 find the perimeter of the rectangle​

Answer 1

Here, Perimeter = ${20\sqrt{2}}$

Thank You

Answer 2

Answer:

Step-by-step explanation:

Construct XY II AD II BC through P.

Since AXYD and APD lie on the same base AD and between the same IIs AD and XY,

ar(APD) = 1/2 ar(AXYD)

=> ar(AXP + DPY) = ar(APD) ————— (1)

Similarly,

Since BXYC and BPC lie on the same base BC and between the same IIs BC and XY,

ar(BPC) = 1/2 ar(BXYC)

=> ar(BXP + CPY) = ar(BPC) ————— (2)

Adding (1) and (2), we get,

ar(ABP + DPC) = ar(APD + BPC) = 48 sq.cm

Therefore, ar(ABCD) = 48 + 48 sq.cm = 96 sq.cm

Area of rectangle = lb sq.units

96 sq.cm = 3x * 2x

16 sq.cm = 6 x^2

16 cm = x

Therefore,

l = 3 * 16 = 48cm

b = 2 * 16 = 32cm

Perimeter = 2(l + b) units = 2(48 + 32) cm = 2 * 80 cm = 160cm

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hope this answer helped :)