Question

In the figure, ABCD is a rectangle of dimensions 4 cm and 6 cm. E and F are mid-points of AB and BC respectively. Find the area of the shaded portion.

Answer 1

Area of the shaded region = area of the rectangle-area of the triangle

Area of the rectangle = length x breadth =4 x 6 =24 sq. cm

As it is is given that E and F are midpoints of AB and CB respectively

This means that AE = EB = 3cm and BF =FC =2cm

It is a right angled triangle. So, base and height of the triangle = base and altitude respectively

We know that area of a triangle = 1/2 x base x height = 1/2 x 2 x 3 = 3 sq. cm

Now area of the shaded region = 24 - 3 = 21 sq. cm

Hope this helps!

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