Question

(In the figure ABCD is a rectangle. PQ is parallel to AC, AD = 6cm, AB = 8cm. Calculate the area of rectangle PQCA)

*24cm²
*60cm²
*48cm²
*40cm²​

Answer 1

Step-by-step explanation:

given figure parallelogram ABCD and parallelogram ABEF are lies between same parallel lines and having same base AB.

∴ Area of parallelogram ABCD = Area of parallelogram ABEF.

⇒ In parallelogram ABEF

⇒ AB=b=4.2 and FP=h.

⇒ Area of parallelogram ABEF=b×h.

⇒ 36=4.2×h.

⇒ h=

4.2

36

⇒ h=8.57cm.

∴ Height of parallelogram ABEF is 8.57cm.