Question

in the figure ABCD is a rhombus ,angle A=3x+60 , angle B=x+3y+10 ,angle C=10y+20 and angle D= 2x+2y . find the value of x and y ,and also find the value of each angles

Answer 1

Answer:

ans is 28

Step-by-step explanation:

In rhombus, Let the line AC and BD intersect at a point called O.

The angle made by this two line at the Center is 90 degree. ( Property of Rhombus)

∠AOB=∠AOD=∠COD=∠COB=90

∠CBD=∠BDA=y ( Alternate Angles)

∠DCA=∠CAB=x ( Alternate Angles)

∴∠DAO=62−x

In triangle AOD,

∠DAO+∠AOD+∠ODA=180

62 - x + 90 + y = 180

y - x = 180 - 90 - 62

y - x = 28