in the figure ABCD is a rhombus angle DAB is equal to 80 degrees find angle CBD& ADB
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As the sides are parallel, and the diagonal bisects the angles.
On, making the figure,
∠ABC = 180°- 80° [parallel line property]
= 100°
∴∠CBD = 100°/2 = 50°
∠ADB = ∠CBD = 50° [ alternate interior angles]
On, making the figure,
∠ABC = 180°- 80° [parallel line property]
= 100°
∴∠CBD = 100°/2 = 50°
∠ADB = ∠CBD = 50° [ alternate interior angles]
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