Question

In the figure ABCD is a rhombus angle DAB is equal to 80 degrees find angle CBD& ADB

Answer 1

both are 50° ...... .......................

Answer 2

∠DAB = 80°
so, ∠ABC = 180°-80° = 100° [ parallel line property]

As we know that the diagonal of parallelogram bisects the angles.
so, ∠CBD = ∠ABC/2 = 100°/2 = 50°
and, ∠ADB = ∠CBD = 50° ( alternate interior angles)