Question

In the figure ABCD is a rhombus are ADC and triangle ABC congruent what can you say about the triangle ABC and BCD

Answer 1

Answer:

since diagonals of a parallelogram bisects it into 2 congruent triangles therefore, triangle ABC~= ADC, (GIVEN)

A diagonal of a rhombus divides it into 4 triangles of equal areas. therefore,

area(AOB)=area(BOC)=area(COD)=area(DOA)

ADD: area AOB + area BOC = area COD + area DOC

    = area(ABC) = area(BCD)

THIS WILL BE THE RELATIONSHIP BETWEEN triangle ABC and triangle BCD.