Question

In the figure ABCD is a rhombus whose diagonal intersect at a point O. If side AB=10 cm and diagonal BD=16 cm, find the length of the diagonal AC.​

Answer 1

Answer:

(ab)2= (ao)2 +(bo)2

(10)2= (x)2 + (8)2

100 = x2 + 64

x2 =100-64

x2 = 36

x = √36

x = 6

Answer 2

Answer:

Given:Ad=10cm BD=16cm

Therefore BD=2OD (diagonal

bisect each other)

Step-by-step explanation:

By Pythagorean theorem in triangle AOD :

(AD) ²=(OA) ²+(OD) ²

(10) ²=(OA) ² +(8) ²

100-64= OA²

36=OA²

√36=OA

Therefore OA=6cm

Therefore AC=2OA

AC=12cm.

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