in the figure, ABCD is a square . A line segment DX cuts the sides BC at X and the diagonal AC at O such that angle COD = 105°. find the value of X
Answers
Answer: x= 60°
Step-by-step explanation:
Given :In the figure ABCD is a square. A line segment DX cuts the side BC at X and the diagonal AC at O such that COD = 105 degree and OXC = x
To find :x
Since DX is a line segment, then
angle COD + angle COX = 180 degrees {Angle sum property}
=> angle COX = 180 -105 = 75 degrees..(1)
Since ABCD is a square and AC is a diagonal , therefore all the angles in a square is 90 degree each and AC bisects the angle in half. {property}
=> angle ACB { also OCX } = 90 /2 =45 degrees...(2)
In traingle COX
=> angle OCX + angle COX + x = 180 degree { sum of angles in a triangle is 180 degree}
=> x = 180 - (45+75) {using eq 1 and 2}
=> x = 60 degrees Answer
I guess you've missed 1 part of the question that OXC= x
:)
Answer:
x° = 60°
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Aayush Makkar
My ID- AayushMakkar
