Question

In the figure, ABCD is a square and E is the mid-point of AD. BE and CF are
joined. Prove that angleECB = angleEBC.​

Answer 1

Consider ∆ABE & ∆CED

AB = DC [sides of square are equal]

angle CDE = angle BAE [all angles of square are 90°]

AE = ED

So ∆ABE = ∆CED