Question

In the figure , ABCD is a square in which CE and DE are the angle bisectors of angle C and angle D, prove that angle CED=angle A =angleB=angleC=angleD​

Answer 1

$\huge \fbox \purple{❥ Answer}$

AS ABCD IS A SQUARE

SO A = B= C= D=90

AS CE AND DE ARE ANGLE BISECTOR

SO <EDC=<DCE= 45

SO DEC= 180 -45-45

=90

HENCE DEC = A= B= C= D

Answer 2

❥ Answer

AS ABCD IS A SQUARE

SO A = B= C= D=90

AS CE AND DE ARE ANGLE BISECTOR

SO <EDC=<DCE= 45

SO DEC= 180 -45-45

=90

HENCE DEC = A= B= C= D