In the figure ABCD is a square M is the mid point of AB, CM is perpendicular to PQ meets AD at P, and CB produced at Q. Prove that PA = BQ
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Answer is in the media. Its fully solved.
We can prove PA=BQ by showing that ∆PAM & ∆QBM are congruent by ASA congruency. And thus it can be proved by CPCT.
We can prove PA=BQ by showing that ∆PAM & ∆QBM are congruent by ASA congruency. And thus it can be proved by CPCT.
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