Question

in the figure ABCD is a square the triangle at the four corners are congruent find the area and the perimeter of the shaded region​

Answer 1

Answer:

area of the square is equals to side into side 20 into 20 is equals to 400 the area of the triangle is equals to of half into 3*3 into off into 3 into 3 it gives 18 400 - 18 is 382 perimeter of square is equals to 4 into side 4 into 20 is equals to 80 perimeter of the triangle is equals to side + side 3 +3+3 =9 80-9 =71

Answer 2

Answer:

side of square=20cm

Area=S×S=20m×20m=400m²

Area of four triangle=[½×3×3]×4=9/2×4=18m²

Area of shaded area=400m²-18m²=382m²

Perimeter of square=S×4=20×4=80m

FGB triangle FB =BG-3m

FG=3×√2=3√2m

FG+LE+KJ+IH=3√2×4 =16.97m

KL+JI+I+G+EF=20-(3×2)×4=(20-6)×4=14×4=56m

Total perimeter of shaded area =16.97m+56m

=72.97m(answer)

THANK YOU