Question

In the figure ABCD is a trapezium .Diagonal of triangle a
bc is 24sqcm and area of triangle amb is 10sq cm

Answer 1

Question:-

In the figure ABCD is a trapezium .Diagonal of triangle a bc is 24sqcm and area of triangle amb is 10sq cm.

Answer:-

Area of the trapezium = h/2 (a + b) 

where a and b are the parallel sides 

h = perpendicular distance between the parallel sides

Area of the trapezium ABCD = AB/2 (AD + BC)

24.5 = (AB/2) (10 + 4)

49 = AB (14)

AB = 3.5 cm

Radius of the quadrant of the circle = AB = 3.5 cm

Area of the quadrant of the circle = 1/4πr²

= 1/4 x 22/7 x 3.5 x 3.5

= 9.625 cm²

Area of the shaded region = Area of the trapezium - Area of the quadrant of the circle

= 24.5 - 9.625

= 14.875 cm²

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