Question

In the figure ABCD is a trapezium in which AD is parallel to BC . If BC is 13 cm , DC is 10 cm and AD is 7 cm .Find the area of the trapezium.

Answer 1

Answer:

hi

Step-by-step explanation:

don't know the answer

Answer 2

Step-by-step explanation:

let the height be x

AD = BC parallel lines

AD = 7 cm

so, other parallel sides be 7 cm to make a rectangle

BC - 7 cm = 6 cm

so, DC = 10 cm and base = 6 cm

height = underroot hypothesis^2 - base^2

= 10^2 - 6^2

= 100 - 36 = 64

height = 64

area of trapezium = 1/2*h* ( a + b )

= 1/2*64*( 13 + 7 )

= 32*20 = 640 cm ^2

area of trapezium = 640^2 cm